本文共 710 字,大约阅读时间需要 2 分钟。
d = {'a': 1}
d.update(b=2) #也可以 d.update({‘b’: 2})print(d)# {'a': 1, 'b': 2}
d.update(c=3, d=4)print(d)# {'a': 1, 'c': 3, 'b': 2, 'd': 4}
d['e'] = 5print(d)# {'a': 1, 'c': 3, 'b': 2, 'e': 5, 'd': 4}
d.update({'f': 6, 'g': 7}) #即d.update(字典)print(d)# {'a': 1, 'c': 3, 'b': 2, 'e': 5, 'd': 4, 'g': 7, 'f': 6}
pop(key)
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
x.pop(1) # pop(key)print(x)# {0: 0, 2: 1, 3: 4, 4: 3}
del dict[key]
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}del x[1]print(x)# {0: 0, 2: 1, 3: 4, 4: 3}
方法
def remove_key(d, key): r = dict(d) del r[key] return r x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} print(remove_key(x, 1)) print(x) # {0: 0, 2: 1, 3: 4, 4: 3} # {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
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